4x^2+.25x-1.1=0

Solution for 4x^2+.25x-1.1=0 equation:

4x^2+.25x-1.1=0

a = 4; b = .25; c = -1.1;
Δ = b2-4ac
Δ = .252-4·4·(-1.1)
Δ = 17.6625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.25)-\sqrt{17.6625}}{2*4}=\frac{-0.25-\sqrt{17.6625}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.25)+\sqrt{17.6625}}{2*4}=\frac{-0.25+\sqrt{17.6625}}{8}
$